Discussion in 'Offtopic' started by Masteraj12, May 6, 2017.
I think you're confusing me with daddy @Masteraj12
Also why did I just see this oml
I tried to work this out and I found myself lost on a lot of things. To start I'm not quite sure why Y is where the victim is (is it allowed to be a negative value). Honestly I just can't figure out this problem, sorry I can't be of help here.
Yeah I got lost too, and the hint my teacher gave just honestly confused me more. Im not sure about negative values to be honest, ever since radians were introduced, I've been lost.
If you want to see the hint they gave you can if you want to.
(angle of entry is 5pi/12)
If youre lost then don't worry or stress about it, its my problem not yours
I actually kinda feel awkward posting about my math problems here cuz I feel i should be tackling them on my own...
Is it on a 2D or 3D plane where the victim an witness are on equal base level with the building. If so I might be able to do it
I believe it is a 3d plane. And yeah the victim and witness are at an equal level with the building
Does YGH form a right angle?
I assume so
I got that the bullet was fired from the 8.65th floor so round it to 9? Is the answer only 5,6 or 7?
you have to assume angle ygw is 90 degrees idk how else you'd do this
so if ygw is 90 degrees, use pythagoras to find side length yg, I got sqrt(50)
then use tan(theta) = opposite/adjacent to find height
tan(5pi/12) = height/sqrt(50)
convert 5pi/12 to degrees = 75
tan(75) = height/sqrt(50)
solve for height then divide by 3.048 to get the floor = 8.65
"The building is a high rise apartment building with ten floors. There were residents home from the 5 th , 6 th, and 7 th floors from a unit facing the road where the victim was shot. There is 3.048m between each apartment floor."
The statement here makes me think that its either floors 5, 6, or 7 which threw me off after my old calculations.
Ive ended with the same answer as you but I wanted to see if anyone took a different approach, because since this one ended with floor 8.66, I don't want to believe this method of solving it was the correct one.
I'll probably end up doing the second half of the assignment which is a report and I'll argue that the shot came from floors 8 or 9, and none of the suspects from floors 5-7 are guilty.
Can someone please explain long multiplication I missed part of math and don't understand it lol
Can u give the problem u are working on???
Like @HaleStorm if you have a specific problem please put it in.
Here is the best I can do to explain long multiplication though. So basically multiplication is just a bunch of adding. 4 times 2 is just adding 2 fours together. So 4 times 2 is 4+4 which is 8. 9 times 9 is 9 nines added together, so 9 times 9 is also 9+9+9.... and so on, which =81. Long multiplication is something hard to do in your head. You need to write it down on paper in order to do it (I have actually practiced long multiplication in my head for 6 years and I still struggle with a lot of problems).
So say we have 220 times 21 (which is a pretty hard one to start with, but it will help you learn). I have created a video which will show you what to do. Here are directions.
So first we start by putting the big number on the very top and the small number on the bottom and set up that line to multiply. You then multiply the ones place for each number, then the tens place of the first number to the ones place of the second number, and finally the hundreds place of the first number to the ones place of the second number. So for this one, you multiply the whole number. 220, by "1". Then, underneath the FIRST NUMBER ON THE RIGHT, you put a 0. This 0 is very important, it's called a place holder 0. Then, after you put that place holder 0, you can multiply again. For bigger numbers, like 300 times 300 or something, you will have to put more place holder 0's because there are three rows. I will also have a video on this one here.
The biggest thing is that the place holder zeros go up each row you have. The first row has no place holder 0's, the second row has one place holder 0, the third row has two place holder 0's, and so on. I highly recommend you go see your teacher after class, your teachers are more than willing to help you learn. Their job is to make you learn. Please do see them and ask them questions, especially since you missed part of the class, they are more than willing to help you. No matter what course you are taking, most teachers are willing to help you learn. If they aren't, they aren't doing their job and need to be fired.
Yeah so basically its like i said in the video.
309,801 is the final answer. Please do ask your teacher for extra help.
Sorry my hand writing isn't the best. I just did your problem by starting with 7 and multiplying it by 8373, then I multiplied 3 to 8373. Make sure you add the zero once you get to the second row!!! Then add all of it together. If you need more help just message me.
Not asking teacher for extra help because I understand now
digs up homework help thread b/c super annoyed at one probability question that I want to know how it works even though I already yolo guessed it on the quiz lol (too lazy to ask teacher tomorrow and wants answer naow)
Actually really annoyed at probability:
A test consists of seven true/false questions. A student who forgot to study guesses randomly on every question. What is the probability that the student answers exactly five questions correctly?
tf how dis work help I tried looking it up lmao, still confusing, some hardcore asian guy plz help *cough* masteraj12 *cough*
Because you have seven questions where the chance you want is 1/2, the chances of 5 right and 2 wrong is 1/2^7, which is 1/128.
I think, anyway.
EDIT: Missed out the fact that you can have 21 different ways of having 5 right and 2 wrong, so it's 21*1/128 which is 21/128.
@Elementlover10 have u looked at combinations and permutations very useful for these questions. If so the amount of ways that the combination of 5 right or 2. Wrong can be shown as 7c5 and 7c2 both giving you an answer of 21 as seen above. Since you want probability you them times the amount of outcomes(2) by itself for however many trials(7) were done so 2^7. When done you will let Luke's answer.
Main thing I want to get across is look into Permutations and Combinations they are super useful for probability.
Doing Algebra 2 and we are focusing on logs, I understand how to do most of it except for this one question on my homework.
(1/2)^x=1 and I need to find X
Separate names with a comma.